Just creating a thread for number puzzles..
First:
Q. if we take away 1 from 4, 5 remains, How??
20 Replies
sajeetharan wrote:
[quote]the answer for the puzzle is
2+5+3=132
3+6+4=380
4+2+7=63
6+3+6=228
8+5+2=?
rule is
a+b+c = p*q where p=(a*b)+1 and q=(b*c)-c
following the above we have
for 8+5+2, p=(8*5)+1=41 and q=(5*2)-2=8 ; p*q=41*8=328
8+5+2=328[/quote]
That was really typical to solve, I could never get it. Please try to post some easy ones, so that it could be answerable.
[quote]the answer for the puzzle is
2+5+3=132
3+6+4=380
4+2+7=63
6+3+6=228
8+5+2=?
rule is
a+b+c = p*q where p=(a*b)+1 and q=(b*c)-c
following the above we have
for 8+5+2, p=(8*5)+1=41 and q=(5*2)-2=8 ; p*q=41*8=328
8+5+2=328[/quote]
That was really typical to solve, I could never get it. Please try to post some easy ones, so that it could be answerable.
Topic Author
S
Sridevi
@hello123
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Created
Tuesday, 15 June 2010 15:23
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Tuesday, 30 November -0001 00:00
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