Challenging question

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2 batsmen each on 94, 7 runs 2 win in 3 balls, both make 100 how ?

This challenging question was asked in an interview
I don't know the answer, do any one know the answer

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tricky..am trying to crack this one,

not getting 100 but 101 and 102 as an answer,lets see.
Yes it was asked in one of the infosys interview,
could it be batsman A hits a six....gets caught on d nxt ball...crease
is changed.... batsman B hits a six again...
First ball : one batsman hit a four,

second ball : same batsman make a shot and take three runs but one run is short and it will be counted as 2 runs...

Third ball : the other batsman hit a six and won the match...

This way they are still unbeaten.....
My answer is the first batsmen hit for four runs in 1st ball

In second ball he hit for 3 runs but the other batsmen wont keep bat in the crease clearly so 1 run will minus.So the first batsmen gets his century.

In the last ball the other batsmen hit for six.He also gets his century. :woohoo:
Sasikanth and satish kail, but both the batsman make century not one batsman
Sasikanth and satish kail, but both the batsman make century not one batsman


Yes they both got century.. Just read it again....
I think a scenario that satifies all the conditions is when the batman at the crease runs himself out after hitting an over boundary to make a crossover possible to enable the batman remaining unbeaten on 94 to hit another over boundary to complete his century!
yes this is really a challenging uestion i try to solve it.
Here again no meaningful answer but a promise to solve it!! Ha Ha!

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Created Thursday, 28 July 2011 12:05
Last Updated Tuesday, 30 November -0001 00:00
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